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黑龙江1990年高考分数线

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篇一:1990年高考阅读

1990年高考阅读

(A)

A well-known old man was being interviewed and was asked if it was correct that he had just celebrated his ninety-ninth birthday.

“That’s right,” said the old man. “Ninety-nine years old, and I haven’t an enemy in the world. They’re all dead.”

“Well, sir,” said the interviewer, “I hope very much to have the honor of interviewing you on your hundredth birthday.”

The old man looked at the young man closely, and said, “I can’t see why you shouldn’t. You look fit and healthy to me!”

66. The old man said he had not an enemy in the world, which shows that he was a very _____.

A. friendly man—he never made any enemies

B. healthy man—he lived longer than all his enemies

C. lucky man—his enemies had all died

D. terrible man—he had got rid of all his enemies

67. When the interviewer said that he hoped very much to have the honor of interviewing the old man again the following year, _____.

A. he was trying to make the old man happy

B. he wished he himself would live another year

C. he did not believe the old man would live to be one hundred

D. he did not believe he would interview the old man again

68. When the old man said “I can’t see why you shouldn’t”, what he meant was _____.

A. “You must try to live another year to interview me again next year.”

B. “Of course you can see me again since you’re so fit and healthy.”

C. “If I live to a hundred years, you should interview me again.”

D. “Unless you live another year, you wouldn’t be able to interview me again.”

69. What kind of man would you say the old man was?

A. He was silly.

B. He was unpleasant.

C. He was very proud and sure of his health.

D. He was very impolite to young people.

(B)

Annealing

Annealing is a way of making metal softer by heating it and then letting it cool very slowly. If metal is heated and then cooled very quickly, for example by dipping it in water, it will be very hard but also very brittle(脆)—that is, it will break easily. Metal that has been annealed is soft but does not break as easily. It is possible to make metal as hard or as soft as is wished, by annealing it. The metal is heated, and allowed to cool slowly, for a certain length of time. The longer the

heated metal takes to cool slowly, the softer it becomes. Annealing can also be used on other materials, such as glass.

70. Annealing can make metal _____.

A. hard and toughB. hard but brittle

C. soft but tough D. soft and brittle

71. Why do people put hot metal in water?

A. To make it hard.B. To make it soft.

C. To make it cool.D. To make it brittle.

72. In annealing, the required hardness of a metal depends on _____.

A. the quantity of water used B. the temperature of the metal

C. the softness of the metal D. the timing of the operation

73. As suggested by the text, how can glass be made less brittle?

A. It can be heated and then cooled quickly.

B. It can be cooled and then heated slowly.

C. It can be heated and then cooled slowly.

D. It can be cooled and then heated quickly.

(C)

“I would almost rather see you dead,” Robert S. Cassatt, a leading banker of Philadelphia, shouted when his twenty-year-old eldest daughter announced that she wanted to become an artist. In the 19th century, playing at drawing or painting on dishes was all right for a young lady, but serious work in art was not. And when the young lady’s family ranked among the best of Philadelphia’s social families, such an idea could not even be considered.

That was how Mary Cassatt, born 1844, began her struggle as an artist. She did not tremble before her father’s anger. Instead, she opposed(抗拒) him with courage and at last made him change his mind. Mary Cassatt gave up her social position and all thought of a husband and a family, which in those times was unthinkable for a young lady. In the end, after long years of hard work and perseverance(坚持), she became America’s most important woman artist and the internationally recognized leading woman painter of the time.

74. How did Mr. Cassatt react(反应) when his daughter made her announcement?

A. He feared for her life. B. He was very angry.

C. He nearly killed her. D. He warned her.

75. What in fact was Mr. Cassatt’s main reason in opposing his daughter’s wish?

A. Drawing and painting was simply unthinkable among ladies in those days.

B. He did not believe his daughter wanted to work seriously in art.

C. He believed an artist’s life would be too hard for his daughter.

D. Ladies of good families simply did not become artists in those times.

76. What made Mary Cassatt’s struggle to become a recognized artist especially

hard?

A. She was a woman.

B. Her father opposed her.

C. She had no social position.

D. She did not come from an artist’s family.

77. What do we know about Mary Cassatt’s marriage?

A. Her marriage failed because she never gave a thought to her husband and

family.

B. She never married because she did not want to be just a wife and mother.

C. After marriage she decided to give up her husband rather than her career.

D. She did not marry because for a lady of her social position to marry below

her was unthinkable.

78. What do we know about Robert Cassatt’s character from the text?

A. He was a cruel man.

B. He was a stubborn(固执的) man.

C. He knew nothing about art.

D. He knew little about his daughter.

79. What do we know about Mary Cassatt’s character?

A. She was brave in going against old ideas.

B. She got tired of always obeying her father.

C. She hated playing at drawing and painting.

D. She did not mind being poor at all.

80. As we can learn from the text, which of the following was generally considered

the most important in the life of a woman in the U.S. in Mary Cassatt’s times?

A. Money.B. Career.

C. Marriage. D. Courage.

(D)

Benin

Benin is one of the smallest African states. It lies in West Africa on the Gulf(海湾) of Guinea, to the south of Burkina Faso and Niger, between Togo on the west and Nigeria on the east.

Benin used to be called Dahomey and was controlled and ruled by France from 1893 to 1960, when it became independent. In 1963 the army general Soglo overthrew(推翻) the first president Maga. Soglo set up an army government and called himself head of state in 1965, but was overthrown and replaced by a civilian(非军人) government in 1967. In December 1969 Benin had another change of power with the army again taking over. In May 1970, Maga and two other men set up a new government, with each of them acting as president in turn for two years. However, half a year after Maga turned over power to the second man Ahomadegbe, the three-man government was overthrown by the army once more and General Kerekou became president. In November 1975 Kerekou changed the name of the nation from Dahomey to Benin, Benin being the name of a 17th century kingdom covering the same place. Kerekou also announced that Benin would be a People’s Republic based on Marxism-Leninism.

81. Which of the following maps shows rightly the positions of Benin and its

neighbouring countries? (Bn=Benin; Tg=Togo; Nr=Niger; BF=Burkina Faso;

Na=Nigeria; GG=Gulf of Guinea)

82. For how long was Benin under France?

A. For over a century.B. For roughly a century.

C. For over half a century. D. Under half a century.

83. For how long was Benin an independent state before it became a People’s

Republic?

A. 15 years. B. 25 years.

C. 20 years. D. 30 years.

84. Choose the right order in which the following people ruled in Benin.

(Ah=Ahomadegbe; Ke=Kerekou; Ma=Maga; So=Soglo)

A. So, Ma, Ah, Ma, Ke B. Ma, So, Ma, Ke, Ah

C. So, Ma, Ke, Ma, Ah D. Ma, So, Ma, Ah, Ke

85. When and how did Benin get its two names—Benin and Dahomey?

A. Dahomey was its oldest name, but it has been replaced by Benin.

B. Benin was its oldest name. The name Dahomey was used later, but has been replaced by Benin again.

C. Dahomey was its oldest name. The name Benin was used later, but has been replaced by Dahomey again.

D. Benin was its oldest name, but it has been replaced by Dahomey.

篇二:1990年高考全国卷数学试题及答案

1990年高考试题

(理工农医类)

一、选择题:在每小题给出的四个选项中,只有一项是符合题目要求的,把所选项前的字母填在题后括号内.

【 】

【 】

(3)如果轴截面为正方形的圆柱的侧面积是S,那么圆柱的体积等于

【 】

(4)方程sin2x=sinx在区间(0,2π)内的解的个数是 (A)1 (B)2 (C)3 (D)4 【 】 (5)

【 】

(A){-2,4} (B){-2,0,4}

(C){-2,0,2,4} (D){-4,-2,0,4}

(7)如果直线y=ax+2与直线y=3x-b关于直线y=x对称,那么【 】

【 】

第 1 页

(C)a=3,b=-2

(D)a=3,b=6

【 】

(A)圆 (B)椭圆 (C)双曲线的一支 (D)抛物线

【 】

(B){(2,3)} (C)(2,3) (D){(x,y)│y=x+1}

【 】

(11)如图,正三棱锥S-ABC的侧棱与底面边长相等,如果E、F分别为SC、AB的中点,那么异面直线EF与SA所成的角等于【 】 (A)90° (B)60° (C)45° (D)30°

(12)已知h>0.设命题甲为:两个实数a,b满足│a-b│<2h;命题乙为:两个实数a,b满足│a-1│<h且│b-1│<h.那么【 】

(A)甲是乙的充分条件,但不是乙的必要条件 (B)甲是乙的必要条件,但不是乙的充分条件 (C)甲是乙的充分条件

(D)甲不是乙的充分条件,也不是乙的必要条件

(13)A,B,C,D,E五人并排站成一排,如果B必须站在A的右边(A,B可以不相邻),那么不同的排法共有【 】 (A)24种 (B)60种 (C)90种 (D)120种

(14)以一个正方体的顶点为顶点的四面体共有【 】 (A)70个 (B)64个 (C)58个 (D)52个

(15)设函数y=arctgx的图象沿x轴正方向平移2个单位所得到的图象为C.又设图象C'与C关于原点对称,那么C'所对应的函数是【 】 (A)y=-arctg(x-2) (B)y=arctg(x-2) (C)y=-arctg(x+2) (D)y=arctg(x+2) 二、填空题:把答案填在题中横线上.

(17)(x-1)-(x-1)2+(x-1)3-(x-1)4+(x-1)5的展开式中,x2的系数等于

第 2 页

(18)已知{an}是公差不为零的等差数列,如果Sn是{an}的前n项的和,

(19)函数y=sinxcosx+sinx+cosx的最大值是

(20)如图,三棱柱ABC-A1B1C1中,若E、F分别为AB、AC

的中点,平面EB1C1F将三棱柱分成体积为V1、V2的两部分,那么V1:V2= 三、解答题.

(21)有四个数,其中前三个数成等差数列,后三个数成等比数列,并且第一个数与第四个数的和是16,第二个数与第三个数的和是12.求这四个数.

第 3 页

第 4 页

(23)如图,在三棱锥S-ABC中,SA⊥底面ABC,AB⊥BC.DE垂直平分SC,且分别交AC、SC于D、E.又SA=AB,SB=BC.求以BD为棱,以BDE与BDC为面的二面角的度数.

第 5 页

篇三:1990年全国高考数学试题

一九九0年全国高考数学试题

理科试题

一.选择题:本题共15个小题;每小题3分,共45分。在每小题给出的四个选项中,只有一项是符合题目要求的。把所选项前的字母填在题后的圆括号内。

(1)方程2log3x?的解是 ( A ) (A)x? (B)x?

19

14

3

(C)x?3 (D)x?9 3

2?

,所得到的向量对3

(2)把复数1+i对应的向量按顺时针方向旋转

应的复数是 ( B ) (A)

?1?3?1?1??1??i ?i (B)2222?1?31?31??1?3

?i(D)?i 2222

(C)

(3)如果轴截面为正方形的圆柱的侧面积是S,那么圆柱的体积等于 ( D ) (A)

SSSSSS (B)(C)S (D) 242?4?

(4)方程sin2x?sinx在区间(0,2?)内的解的个数 ( C )

Y

4

? ( 5)已知右图是函数 y?2sin(?x??)(|?|?) 2(A)1 (B)2(C)3(D)

( C )图像,那么

10?10?

(A)??,??(B)??,???

116116

(C)??2,?? (D)??2,??? (6)函数y?

sinx|cosx|tgx|ctgx|

的值域是 ( B ) ???

|sinx|cosx|tgx|ctgx

?6?6

(A){-2,4} (B){-2,0,4} (C){-2,0,2,4} (D){-4,-2,0,4} (7)如果直线y=ax+2与直线y=3x-b关于y=x对称,那么 ( A ) (A)a?,b?6 (B) a?,b??6 (C)a?3,b??2 (D) a?3,b?6 (8)极坐标方程4?sin2

?

?5表示的曲线是 ( D ) 2

13

13

(A)圆(B)椭圆(C)双曲线的一支 (D)抛物线 (9)设全集I?{(x,y)|x,y?R},集合M?{(x,y)|

????????

y?3

?1}, x?2

N?{(x,y)|y?x?1}那么M?N等于 ( B )

(A)?(B){(2,3)} (C)(2,3) (D){(x,y)|y=x+1} (10)如果实数x,y满足等式(x-2)2+y2=3,那么的最大值是 (A) (B)

1

2

yx

(C) (D)3( D ) 32

CB FA

(11)如图,正三棱锥S-ABC的侧棱与底面边长相等,如果E、F分别为SC、AB的中点,那么异面直线EF与SA所成角等于 ( C )

(A)900 (B)600 (C)45(本文来自:Www.dXF5.com 东星资源 网:黑龙江1990年高考分数线)0 (D)300

(12)已知h>0,设命题甲为:两个实数a,b满足|a-b|<2h;命题乙为:两个实数a,b满足

|a-1|<h且|b-1|<h.那么 ( B ) (A)甲是乙的充分条件,但不是乙的必要条件

(B)甲是乙的必要条件,但不是乙的充分条件 (C)甲是乙的充要条件

(D)甲不是乙的充分条件,也不是乙的必要条件

(13)A,B,C,D,E五人并排站成一排,如果B必须站在A的右边(A,B可以不相邻),那么不同的排法共有 ( B ) (A)24种 (B)60种 (C)90种(D)120种 (14)以一个正方体的顶点为顶点的四面体共有 ( C ) (A)70个(B)64个 (C)58个(D)52个 (15)设函数y?arctgx的图像沿x轴正方向平移2个单位所得到图象为C。又设图象C?与C关于原点对称,那么C?所对应的函数是 (A)y??arcg(x?2)(B)y?arcg(x?2) ( D ) (C)y??arcg(x?2)(D)y?arcg(x?2)

二.填空题:本大题共5小题,每小题3分,共15分。把答案填在题中横线上。

x2y2

(16)双曲线??1的准线方程____________

169

答案:y??

16 5

(17)(x-1)-(x-1)2+(x-1)3-(x-1)4+(x-1)5的展开式中,x2的系数等于__________ 答案:-20

(18)已知{an}是公差不为零的等差数列,如果Sn是{an}的前n项的和,那么lim

nan

等于___________

n??Sn

答案:2

(19)函数y?sinxcosx?sinx?cosx的最大值是___________ 答案:?2

(20)如图,三棱柱ABC-A1B1C1中, 若E、F分别为AB、AC的中点,平面EB1C1F将三棱柱分成体积为V1、V2的两部分,那么V1:V2=_____ 答案:7:5

三.解答题:本大题共6小题,共60分. (21)(本小题满分10分)

有四个数,其中前三个数成等差数列,后三个数成等比数列,并且第一个数与第四个数的和是16,第二个数与第三个数的和是12。求这四个数。

(a?d)2

. 解:设四个数依次为a-d,a,a+d,a

2?(a?d)

(a?d)??16依题意,有??a??a?(a?d)?12

12

A B1A B E

(1) (2)

由(2)式得d=12-2a (3) 将(3)代入(1)式得

(a?d)2

[a?(12?2a)]??16.整理得:a2?13a?36?0.

a

解得:a1?4,a2??6

从而得所求四个数为0,4,8,16.或15,9,3,1. (22)(本小题满分8分)

已知sin??sin??,cos??cos??,求tg(???)的值。 解:由已知得

sin??sin??2sin

??????1

cos?,224

??????1

cos??cos??2coscos?,

223

1413

???3

?. 24

???2tg

24所以tg(???)??.(图解二略) ???71?tg2

2

两式相除得tg

(23)(本小题满分8分)

如图,在三棱锥S-ABC中,SA⊥底面ABC,AB⊥BC。DE垂直平分SC,且分别交AC、SC于D、E。

S

又SA=AB,SB=BC。求以BD为棱,

以BDE与BDC为面的二面角的度 A C

数 B

解:由于SB=BC,且E是SC的中点,因此BE是等腰三角形SBC的底边SC的中线,所以SC⊥BE。 又已知SC⊥DE,BE∩DE=E, ∴SC⊥面BDE,∴SC⊥BD

又∵SA⊥底面ABC,BD在底面ABC上,∴SA⊥BD而SC∩SA=S ∴BD⊥面SAC∵DE=面SAC∩面BDE,DC=面SAC∩面BDC, ∴BD⊥DE,BD⊥DC。∴∠EDC是所求的二面角的平面角 ∵SA⊥底面ABC,∴SA⊥AB,SA⊥AC。

设SA=a,则AB=a,BC=SB=2a又因为AB⊥BC,所以AC=3a

标签:年高 黑龙江 分数线 1990年高考录取分数线 1990年高考试题